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A gas sample has a temperature of 24 ∘C with an unknown volume. The same gas has a volume of 464 mL when the temperature is 81 ∘C, with no change in the pressure or amount of gas.What was the initial volume, in milliliters, of the gas?Express your answer to three significant figures and include the appropriate units.

User Ccsv
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Step-by-step explanation:

We have a sample of gas that has a temperature of 24°C and an unknown volume. The same sample at the same pressure has a volume of 464 mL at 81°C. We have to find the initial volume.

To solve our problem we can apply the formula that shows us the relationship between the volume and temperature of a gas sample at constant pressure.

V₁/T₁ = V₂/T₂

Where V₁ and T₁ are the initial temperature and volume and V₂ and T₂ are the final volume and temperature. We already know some of these values, but we have to convert the temperatures from °C to Kelvins, because we have to work with an absolute temperature scale (to not divide by zero).

V₁ = ?

T₁ = (273.15 + 24) K

T₁ = 297.15 K

V₂ = 464 mL

T₂ = (273.15 + 81) K

T₂ = 354.15 K

Finally we can replace these values in the formula and solve it for V₁ to get the answer to our problem.

V₁/T₁ = V₂/T₂

V₁ = V₂ * T₁/T₂

V₁ = 464 mL * 297.15 K/(354.15 K)

V₁ = 389 mL

Answer: the initial volume was 389 mL.

User Johann Bzh
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