Question

Express (81^1/2) ^5 in simplest radical form

Answer 1

`9^5`

1) Let's simplify this expression, making use of the properties of the exponents.

2) So we can write it out:

`\begin{gathered} (a^b)^c=a^(bc) \\ (81^{(1)/(2)})^5=((9^2)^{(1)/(2)})^5=(9^{(2)/(2)})^5=9^5 \end{gathered}`

Note that we rewrote 81 as power and then applied the property of the exponents