Question

an adiabatic compressor compresses air at 150 kpa and 400k to 2 mpa. what is the exit temp of the air if it is an isentropic process

Answer 1

Answer;

The exit temperature = 5333.33 K

Step-by-step explanation:

The inlet pressure: P₁ = 150 kpa

The inlet temperature T₁ = 400K

The exit pressure, P₂ = 2 MPa = 2000 kPa

The exit tenperature, T₂ = ?

The relationship between temperature and pressure for an isentropic process is shown below

`(T_2)/(T_1)=(P_2)/(P_1)`

Substitute the given parameters into the formula and solve for T₂

`\begin{gathered} (T_2)/(400)=(2000)/(150) \\ \\ T_2=400((2000)/(150)) \\ \\ T_2=5333.33K \\ \end{gathered}`

The exit temperature = 5333.33 K