Answer:
140 km/h
Step-by-step explanation:
If you have a speed of v1 the first half of the trip and a speed of v2, the second half of the speed, the average speed will be

Solving for v2, we get:

Then, we can replace the average speed Vavg = 100 km/h and the speed of the first half v by 60 km/h
![\begin{gathered} v_2=2(100\operatorname{km}/h)-60\operatorname{km}/h \\ v_2=200\operatorname{km}/h-60\operatorname{km}/h \\ v_2=140\operatorname{km}/h \end{gathered}]()
Therefore, the speed in the second half of the trip must be 140 km/h