Given:
Vertices (-8, 2), (4, 14), (16, 2) and (4, -10).
Required:
To find the figure that is made by the vertices.
Step-by-step explanation:
Let A (-8, 2), B(4, 14), C(16, 2) and D(4, -10).
Then find the length of each side by using the distance formula.




All sides are equal.
AB =BC = CD = AD
We know that the figure in which all sides are equal is called a square.
Final Answer:
Option 2 is the correct answer.