So we need to solve the following system of equations:

We must use the method of substitution. This means that the first step is to choose one of the equations and clear one of the variables, either x or y. So let's pick the first one and clear x:

Now we have an expression for x where x is a function of y. The next step is to take the right side of this expression and substitute the x on the second equation with it:

Now we find y:

Now we take the expression we find for x and substitute y=1 on it:

So the answer is:

Which is the point (-1,1) in the cartesian grid.