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while on a luge run in the olympics the sled (mass=157 kg) rounds a horziontal curve of radius 5.8m with a speed of 18.5 m/s assuming there is no friction what is the normal force exerted by the track
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while on a luge run in the olympics the sled (mass=157 kg) rounds a horziontal curve of radius 5.8m with a speed of 18.5 m/s assuming there is no friction what is the normal force exerted by the track on the sled

User Eyn
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In a circular motion the normal force is also called centripetal force. The centripetal force is given by:


F=(mv^2)/(r)

where m is the mass, v is the velocity and r is the radius.

Plugging the values given we have:


undefined

User Fbastien
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