What is the solution of 4(k-8)=32+4k

asked Nov 12, 2023 67.6k views

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$\begin{gathered} 4(k-8)=32+4k \\ 4k-32=32+4k \\ 4k-32+32=32+4k+32 \\ 4k=64+4k \\ 4k-4k=64+4k-4k \\ 0=64 \end{gathered}$

answer: equation has no solution

Aled Sage answered Nov 17, 2023

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