Question

The specific heat of a certain type of cooking is 1.75 J(g ⋅ °C). How much heat energy is needed to raise the temperature of 2.44 kg of this oil from 23 °C to 191 °C? q = ___________ J

Answer 1

The heat abvsorved by a substance is calculated according to the following equation:

`q=m* C*\Delta T`

Where q is the heat, m is the mass of the substance, C is the specific heat and AT is the temperature increment. Therefore we have all the required data to solve this problem:

`q=2440\text{ g }*1.75(J)/(g\cdot\degree C)*(191\degree C-23\degree C)=717360\text{ J}`

Just be sure all quantities are in the corresponding units