In this scenario, there are only two outcomes. It is either the household is tuned to Lett3rs or not. The outcomes are independent. This means that we can apply the binomial probability. the formula is expressed as
P(x) = nCx * p^x * q^(n - x)
where
n = number of trials
x = number of succeses
p = probability of success
q = probability of failure
From the information given,
n = 14
p = 16% = 16/100 = 0.16
q = 1 - 0.16 = 0.84
1) P(none) = P(x = 0)
Thus,
P(none) = 14C0 * 0.16^0 * 0.84^(14 - 0)
P(none) = 0.087
2) P(at least one) = P(x ≥ 1) = 1 - P(x = 0)
P(at least one) = 1 - 0.087
P(at least one) = 0.913
P(at most one) = P(x = 0) + P(x = 1)
P(x = 1) = 14C1 * 0.16^1 * 0.84^(14 - 1) = 0.2322
P(at most one) = 0.087 + 0.2322
P(at most one) = 0.32