Answer:
2.0 vertical feet per second
Step-by-step explanation:
First, determine the vertical distance covered by Mark.
![\begin{gathered} \text{Vertical Distance=}8585-6574 \\ =2011\text{ ft} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hluoled26d93eke9unw0d6lbmkdt48j4l5.png)
Next, convert the fastest reported time for running up the incline( 16 minutes and 42 seconds) to seconds.
![\begin{gathered} 16\text{ mins 42 seconds = (}16*60)+42 \\ =960+42 \\ =1002\text{ seconds} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/uy9hx13vmzrpo7ar6pjasysfnayurm5mfl.png)
Finally, determine Mark's vertical feet per second:
![\begin{gathered} \text{Mark's vertical sp}eed\text{ per second=}(2011)/(1002) \\ =2.007\text{ ft per second} \\ \approx2.0\text{ ft per second (to 1 decimal digit)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gwmig7efcubed5kli0y9j7us8nb2sej8z5.png)
Mark climbed at a rate of 2.0 vertical feet per second.