141k views
2 votes
GPAs at CCSU are normally distributed with a mean of 2.27 and a standard deviation of 0.59. Find the z-score for a GPA of 3.

GPAs at CCSU are normally distributed with a mean of 2.27 and a standard deviation-example-1
User Sherly
by
7.7k points

1 Answer

5 votes

GIVEN:

We are given the following data and measures of central tendency;


\begin{gathered} Mean(\mu)=2.27 \\ \\ Standard\text{ }deviation(\sigma)=0.59 \\ \\ GPA(x)=3 \end{gathered}

Required;

To find the z-score for a GPA of 3.0

Step-by-step solution;

The z-score will be determined by the formula;


z-score=(x-\mu)/(\sigma)

We now substitute the values and we have;


\begin{gathered} z-score=(3-2.27)/(0.59) \\ \\ z-score=(0.73)/(0.59) \\ \\ z-score=1.23728813559 \\ \\ z-score\approx1.237 \end{gathered}

ANSWER:

The fourth option is the correct answer.


1.237

User AKASH MATHWANI
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.