Question

Indicate in standard form the equation of the line passing through the given points, writing the answer in the equationbox below.R6, 2), Q8, -4)

Answer 1

The equation of the line in two point form is given by:

`(y-y_1)/(x-x_1)=(y_2-y_1)/(x_2-x_1)`

Substitute the points to get:

`\begin{gathered} (y-2)/(x-6)=(-4-2)/(8-6) \\ (y-2)/(x-6)=-3 \\ y-2=-3x+18 \\ 3x+y-20=0 \end{gathered}`

Hence the equation of the line is 3x+y-20=0