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Find the area of a sector with a central angle of 170° and a radius of 17 millimeters. Round to the nearest tenth. 1) 857.5 mm22) 100.9 mm23) 428.7 mm24) 25.2 mm2

User Martinr
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1 Answer

3 votes

Problem statement: we have been given a task to find the area of the sector.

We are given some parameters:


\begin{gathered} \text{central angle=170}^0 \\ \text{radius}=17\operatorname{mm} \\ \end{gathered}

Method: We will apply the formula:


\begin{gathered} A=(\theta)/(360)*\pi r^2 \\ \text{where} \\ \theta=\text{ central angle} \\ r=17\operatorname{mm} \\ A=\text{Area of the sector} \\ \pi=(22)/(7) \end{gathered}

Thus, applying the formula


A=(170)/(360)*(22)/(7)*17^2


A=428.7\operatorname{mm}^2

The area of the sector is 428.7mm²

The answer is option 3

User Oleksandr Skrypnyk
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