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There are 53 members on the board of directors for a certain non-profit institution. If they must elect a chairperson, first vice chairperson, second vice chairperson, and secretary, how many different slates of candidates are possible? There are _ different slates of candidates possible.please answer the question above.

User Donnyton
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For this problem the order of selection matter (the first person is the chairperson, the second the first vice chairperson and so on); since this is the case we need to use permutations. The permutation is given by:


_nP_k=(n!)/((n-k)!)

we have a total of 53 members and the slates contain 4 people, then we have:


_(53)P_4=(53!)/((53-4)!)=7027800

Therefore, there are 7,027,800 different slates of candidates.

User Dccollie
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