When we are solving an equation the goal is to find the values which would make that equation equal to "0". Therefore if we have a quadratic equation of the following form:
![ax^2\text{ + bx + c = 0}](https://img.qammunity.org/2023/formulas/mathematics/college/5g12tkramqxsv41d83rhxbcqeorituzjv5.png)
If it is possible to express it in a form with two perfect squares we can rewrite it as follows:
![(x-r)^2\text{ = 0}](https://img.qammunity.org/2023/formulas/mathematics/college/wdz2k0e8qhxn6ie2gphkh3aqmuu1vp3o4x.png)
Where "r" is the root of the equation, its solution, therefore this would be the best method for solving it. Let's check an example:
![\begin{gathered} x^2\text{ - 4x + 4 = 0} \\ (x\text{ -}2)^2\text{ = 0} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r4lne2g05felqc19drb3r5e889izouixbq.png)
The answer to this quadratic equation is 2.