Given:
Two resistors are connected in parallel.
The resistance of resistor 1 is

The resistance of resistor 2 is

The value of the voltage source is

Required:
(a)The equivalent resistance of the circuit.
(b) The current in each branch of the resistor.
(c) The total current in the circuit.
Step-by-step explanation:
(a) In a parallel circuit, the equivalent resistance can be calculated as

(b) In a parallel circuit, the voltage across each resistor is the same.
The current through the resistor R1 can be calculated according to Ohm's law

The current through the resistor R2 can be calculated as

(c) The total current in the circuit is the sum of the current through each branch.
Thus, the total current can be calculated as

Final Answer:
(