82.8k views
5 votes
The half-life of gold-194 is approximately 1.6 days.How much of a 7gram sample of gold-194 would remain after 3days? Round to three decimal places.

User Minions
by
8.0k points

1 Answer

4 votes

Given that the half-life of gold-194 is approximately 1.6 days.

We can find how much of a 7-gram sample of gold-194 would remain after 3days using the formula below;


\begin{gathered} A=A_0((1)/(2))^{\frac{T}{h_{}}} \\ \text{Where A = final amount}=\text{?} \\ A_0=initial\text{ amout}=7\text{ grams} \\ T\text{ =Time}=3\text{days} \\ h=\text{ half life}=1.6\text{days} \end{gathered}

We would then substitute the parameters into the formula above.


\begin{gathered} A=7(0.5)^{(3)/(1.6)} \\ A=7(0.5)^(1.875) \\ A=1.908 \end{gathered}

Therefore, the amount of a 7gram sample of gold-194 would remain after 3days is;

Answer: 1.908 gram



User Lenette
by
7.8k points

Related questions

asked May 3, 2021 216k views
AnDx asked May 3, 2021
by AnDx
8.5k points
2 answers
1 vote
216k views
asked Jul 27, 2024 25.0k views
VISHMAY asked Jul 27, 2024
by VISHMAY
8.6k points
1 answer
4 votes
25.0k views
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories