Question

2) p(x) = x² + 3; Find p(1)

Answer 1

`p(1)=4`

Step-by-step explanation

Step 1

to find p(1) just replace the value of x in the equation

`p(x)=x^2+3`

when x=1

`\begin{gathered} p(x)=x^2+3 \\ p(1)=1^2+3 \\ p(1)=1+3 \\ p(1)=4 \end{gathered}`

I hope this helps you