Question

How many mL of 0.200 M KBr would be required to make a 0.0715 M solution of KBr when diluted to 175.0 mL with water?

Answer 1

`\text{ The volume is 62.5625 mL}`

Explanation;

Here, we want to get the volume of KBr that would be required

Mathematically, from the dilution formula, we have it that:

`C_1V_1=C_2V_2`

We have it that:

C1 is the concentration of the KBr initially before dilution with water which is 0.2M

V1 is the initial volume that we want to calculate

C2 is the final concentration after dilution which is 0.0715 M

V2 is the final volume which is 175mL

Substituting the values, we have it that:

`\begin{gathered} 0.2\text{ }* V_1\text{ = 175 }*\text{ 0.0715} \\ V_1\text{ = }(175*0.0715)/(0.2)\text{ = 62.5625 mL} \end{gathered}`