Question

Calculate an estimate for the maximum number of drinks a 110lb female can consume without going over 0.08 BAC if she plans on leaving the party in 2 hours.

Answer 1

we have the following:

The formula is:

`B=-0.015\cdot t+(2.84\cdot N)/(W\cdot g)`

replacing,

where

B is blood alcohol content

t is the time

N is the maximum number of drinks

W is the weight

and g a gender constant (0.55 for wormen)

`\begin{gathered} 0.08=-0.015\cdot2+(2.84\cdot N)/(110\cdot0.55) \\ \\ 0.08=-0.03+0.0469N \\ N=(0.08+0.03)/(0.0469) \\ N=2.34\cong2 \end{gathered}`

therefor,e th