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What are the coordinates of the vertex of the parabola y= x2 + 4x – 6?

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We have the equation of a parabola.

We can express the coordinates of the vertex (h,k) using the coefficients of the parabola:


\begin{gathered} h=-(b)/(2a) \\ k=f(h) \end{gathered}

As the parabola is y=x²+4x-6, the expression for h and k is:


\begin{gathered} h=-(b)/(2a)=-(4)/(2\cdot1)=-2 \\ k=f(-2)=(-2)^2+4\cdot(-2)-6=4-8-6=-10 \end{gathered}

Then, the coordinates of the vertex are (h,k) = (-2,-10).

Answer: The vertex is (-2,-10)

User Haagenti
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