Question

A sample of potassium-hild has a half-ife of 5.63 years. How much of a 200.g sample will-remain after 36 year's

Answer 1

Given data

*The half lifetime of potassium-hild is T = 5.63 years

*The given amount is N = 200.0 g

*The given time is t = 36 year

The expression for the radioactivity decay is given as

`N=N_0((1)/(2))^{(t)/(T)}`

Substitute the values in the above expression as

`\begin{gathered} N=200((1)/(2))^{(36)/(5.63)} \\ N_{}=2.63\text{ g} \end{gathered}`