Question

A negative charge of -0.0005 C and a positive charge of 0.0007 C are separated by 0.83 m. What is the force between the two charges?

Answer 1

This is realty hard question

Answer 2

-4572.51 N

Step-by-step explanation

Given:

• The charge of one particle, q₁ = -0.0005 C

,

• The charge of a second particle, q₂ = 0.0007 C

,

• The distance between the charged particles, r = 0.83 m

Find:

• The force between the two charges. F

The force between two charged particles, q₁ and q₂, separated by a distance r, is given by Coulomb's Law,

`F=k\cdot\frac{q_1q_2_{}}{r^2}`

Where k is Coulomb's constant and has a value of approximately 9x10⁹ N*m²/C².

Replace the known values in the equation above and solve to obtain F,

`F=9*10^9(N\cdot m^2)/(C^2)\cdot(-0.0005C\cdot0.0007C)/(0.83^2m^2)\approx-4572.51N`

Hence, the force between the two charges is -4572.51 N. The negative sign indicates that this force is attractive.