Question

Help please! Answer both, it's all one question.2 0 C H A R E C T E R S

Answer 1

`\begin{gathered} Question\text{ 8} \\ \text{square} \\ \text{Area = 64yd}^2 \\ \text{square area = side}^2 \\ \text{side}^2=\text{64yd}^2 \\ \sqrt[]{\text{side}^2}=\sqrt[]{\text{64yd}^2} \\ side\text{ =8yd} \\ The\text{ square's side is 8yd} \\ \\ \text{Question 9} \\ \text{Triangle} \\ base=\text{ }10.5in \\ \text{height}=14in \\ \text{Triangle's area=}(base\cdot height)/(2) \\ \text{Triangle's area=}(10.5\cdot14)/(2) \\ \text{Triangle's area=}(147)/(2) \\ \text{Triangle's area=73.5} \\ \text{The triangle's area is 73.5in}^2 \end{gathered}`