167k views
5 votes
The hypotenuse of right triangle is 25 CM and it's perpendicular distance is 7 CM, find the length of it's base.

The hypotenuse of right triangle is 25 CM and it's perpendicular distance is 7 CM-example-1
User Nahn
by
5.5k points

1 Answer

5 votes

The hypotenuse of a right triangle is given to be 25cm and its perpendicular distance is 7cm. It is required to find the length of the base(b).

A sketch is shown below:

Apply the Pythagorean Theorem which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of its perpendicular and base.

It follows from the theorem that:


b^2+7^2=25^2

Solve the equation for b:


\begin{gathered} \Rightarrow b^2=25^2-7^2=625-49 \\ \Rightarrow b^2=576 \\ \Rightarrow b=√(576)=24 \end{gathered}

The length of the base is 24cm.

The hypotenuse of right triangle is 25 CM and it's perpendicular distance is 7 CM-example-1
User CharlesLeaf
by
5.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.