The triangle ABC is an isosceles with AB=AC.
BC=48
Now given that
DE:DF=5:7.
Since DE is perpendicular to AB and DF is perpendicular to AC, therefore,
BD:DC=5:7
It happens because as DE:DF=5:7, the ratio of the area of the two reight angle triangles is also 5:7.
So, their base must be in the same ration.
Now, two sides are in same ratio, by default, their third sides i.e., BD and DC have the ratio 5:
Since, BC=48, therefore,
![\begin{gathered} DC=(7)/(12)*48 \\ =28 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mv50ozp6dqldyxqua0xo477h3dwj10ankz.png)
Hence, the correct option is (D).