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Factor 3x^2y^2 - 6xy^2

User Thameem
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From the binomial:


3x^2y^2-6xy^2

We can factor out the GCF by factoring out the GCF of the coefficients, and the lowest power of each variable.

The GCF of 3 and 6 is 3.

The lowest power of x is 1.

The lowest power of y is 2.

Then, we can factor out:


3xy^2

Multiply each term by:


(3xy^2)/(3xy^2)

Which does not change the meaning of the expression, since that fraction is equal to 1:


\begin{gathered} 3x^2y^2-6xy^2=3x^2y^2*^{}(3xy^2)/(3xy^2)-6xy^2*^{}(3xy^2)/(3xy^2) \\ =3xy^2(\frac{3x^2y^2^{}}{3xy^2}-(6xy^2)/(3xy^2)) \\ =3xy^2(x-2) \end{gathered}

Therefore:


3x^2y^2-6xy^2=3xy^2(x-2)

User Comocomocomocomo
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