children ticket:47
Adult ticket :13
Step-by-step explanation
Step 1
set the equations
Let x represents the number of children's ticket
let y represent the number of adult tickets,
cost of a children ticket: $ 11
cost of a adult ticket: $ 17
so
a)she purchased 60 tickets, so
hence

B)she spent a total fo $738, hence

Step 2
Solve the equations
a) isolate the x value in equation (1) and replace in equation (2)

now,replace in equation(2)

therefore,
the number of adult tickets is 13
b)now, replace the y value in equation (1) and solve for x

therefore,
the number of children ticket 47
I hope this helps you