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Find the value of Angle S and round it off to the nearest Tenth.

Find the value of Angle S and round it off to the nearest Tenth.-example-1
User Negacao
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From the figure, the only information given is the measure of its Hypotenuse and the Adjacent Side. The triangle also has 90 degrees interior angle, thus, this triangle is a right triangle and we can apply this Trigonometric Function:


\text{Cosine(}\Theta)\text{ = Cosine (}\angle\text{S) = }\frac{Adjacent\text{ Side}}{Hypotenuse}

Given the following information:

Hypotenuse = 7

Adjacent Side = 6

Let's now find the value of Angle S.


\text{Cosine(}\Theta)\text{ = Cosine(}\angle S)=\frac{Adjacent\text{ Side}}{Hypotenuse}\text{ }\rightarrow\text{ Cosine(}\angle S)\text{ = }(6)/(7)
\text{ }\angle S\text{ = }\cos ^(-1)((6)/(7))
\angle S=31.002719^(\circ)

Rounding it to the nearest Tenth, we get:


\angle S=31.002719^(\circ)=31.0^(\circ)

User Wouter Schut
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