Question

Find the inversef(n)=-3/ n+1 +1

Answer 1

In order to find the inverse of the function f(n), we just need to switch f(n) by n, and switch n by f^-1(n) in the function. Then, we isolate f^-1(n). So we have that:

`\begin{gathered} f(n)=-(3)/(n+1)+1 \\ n=-(3)/(f^(-1)(n)+1)+1 \\ -(3)/(f^(-1)(n)+1)=n-1 \\ (3)/(f^(-1)(n)+1)=1-n \\ 3=(f^(-1)(n)+1)(1-n) \\ f^(-1)(n)+1=(3)/(1-n) \\ f^(-1)(n)=(3)/(1-n)-1 \end{gathered}`

So the inverse of f(n) is 3/(1-n) - 1