Question

Using the binomial theorem expression to expand (4a+7b)^8, what would you substitute for the values of a and b?

A. a=11 and b=8


B. a=4a and b=7b


C.a=4 and b=7


D. a=8 and b=7

Answer 1

B
That is the correct answer, hope it helps my dudes!

Answer 2

B.
`a = 4\cdot a` and
`b = 7\cdot b`.

Explanation:

The Binomial Theorem states that a binomial of the form
`(a+b)^(n)`,
`a, b\in \mathbb{R}` can be expanded in the following form:

`(a+b)^(n) = \Sigma \limits_(i=0)^(n) (n!)/(k!\cdot (n-k)!) \cdot a^(n-i)\cdot b^(i)` (1)

If we have
`(4\cdot a + 7\cdot b)^(8)`, then
`a = 4\cdot a` and
`b = 7\cdot b`. In a nutshell, correct answer is B.