Question

How many moles are in 5.68 g of ferric oxide? (Fe2O3)

Answer 1

0.036 mole

Step-by-step explanation:

Fe = 55.845 g

O = 16 g

Fe2O3 = 2(55.845) + 3(16) = 159.69 g

1 mole of Fe2O3 has 159.69 g

so the #mole of 5.68 g = (1 x 5.68)/159.69 = 0.036