Question

I need help with this practice I attempted this practice previously and my attempt is in the picture

Answer 1

We will draw a sketch for the given triangle to find its area

The area of the triangle will be

`A=(1)/(2)* XY* ZM`

Since ZX = ZY = 7, then the triangle is isosceles

Then the height ZM will bisect the base XY

Then we can find ZM by using Pythagoras Theorem

`\begin{gathered} ZM=\sqrt[]{7^2-3^2} \\ ZM=\sqrt[]{49-9} \\ ZM=\sqrt[]{40} \\ ZM=2\sqrt[]{10} \end{gathered}`

Since XY = 6, then

The area of the triangle is

`\begin{gathered} A=(1)/(2)*6*2\sqrt[]{10} \\ A=6\sqrt[]{10}\text{ square units} \end{gathered}`