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If the length and width of a rectangle each change by a factor of nine, what happens to the area of the rectangle?

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Answer:

The area of the rectangle changes by the factor of


9^2

Step-by-step explanation:

Let l and w represent the length and width of the rectangle respectively.

The area is

A = lw

If these change by a factor of nine, then we have:

9l and 9w

The area, which is the product of the length and width becomes:


\begin{gathered} A=9l*9w \\ =9^2lw \\ =9^2A \end{gathered}

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