Let be "a" the number of medals that Country A won, "b" the number of medals that Country B won, and "c" the number of medals that Country C won.
You can set up the following System of equations using the information given in the exercise:
![\begin{cases}a+b+c=119 \\ b=c+7 \\ a=b+c+33\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/college/mk6n0x1ju7ixn6i9oasqnwb13tsw1nc0q9.png)
In order to solve the System of equations, you can follow these steps:
1. Substitute the second equation into the third equation:
![\begin{gathered} a=b+c+33 \\ a=(c+7)+c+33 \\ a=2c+40 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/djcbzkh8atb9ldb8ie815fdav7lm4touuz.png)
2. Substitute this new equation and the second original equation, into the first original equation:
![(2c+40)+(c+7)+c=119](https://img.qammunity.org/2023/formulas/mathematics/college/qcxbsdvhzxln2istfwfzwxqr7li8sb8iqo.png)
3. Solve for "c":
![\begin{gathered} 4c+47=119 \\ 4c=119-47 \\ \\ c=(72)/(4) \\ \\ c=18 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5n2kmxjcnfjx3fcvqd240b82rejm6xgtrl.png)
4. Knowing the value of "c", you can substitute it into the second original equation and then evaluate, in order to find the value of "b":
![\begin{gathered} b=(18)+7 \\ b=25 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/a8g2ercpo6r1uzbfypvhjn0ypqfj5xqa88.png)
5. Knowing the value of "b" and "c", you can substitute them into the third original equation and then evaluate, in order to find the value of "a":
![\begin{gathered} a=b+c+33 \\ a=(25)+(18)+33 \\ a=76 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/sneti5iyhtv5a6e9npges47oxzv1v491re.png)
Therefore, the answer is:
- Country A won 76 medals.
- Country B won 25 medals.
- Country C won 18 medals.