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What is the pressure of an 8.5 L cylinder filled with 23.5 grams of nitrogen gas at a temperature of 298 K?

User NitroMedia
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To solve this question, we need to use the Clapeyron equation. The Clapeyron equation is a mathematical expression that relates quantities such as pressure (P), volume (V), temperature (T) and the number of particles (n) that make up an ideal gas.

The formula is PV = nRT.

First, let's transform 23.5 grams fo nitrogen gas (N2) into moles using its molar mass and the following formula: moles = mass/molar mass

molar mass of N2 = 28 g/mol

moles = 23.5/28 = 0.839 moles

Now let's use the formula PV = nRT

where:

P = ???

V = 8.5 L

n = 0.839 moles

R = 0.082 atm.L/K.mol

T = 298 K

P x 8.5 = 0.839 x 0.082 x 298

P = 20.51/8.5

P = 2.41 atm

Answer: the pressure is 2.41 atm

User Akiller
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