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the length of a rectangle is four times it's width. if the perimeter is at most 106 centimeters, what is the greatest possible value for the width?

User Sheray
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Lenght of a rectangle: L

Widht of the rectangle: W

Perimeter of the rectangle: P

length of a rectangle is four times it's width: L = 4W

Perimeter is at most 106: P <= 106

Perimeter is 2L + 2W: P = 2L + 2W

P <= 106

if we use the value of P = 2L + 2W, we can write:

2L + 2W <= 106

Since L = 4W, then we can write this equation:

2L + 2W <= 106

2(4W) + 2W <= 106

8W + 2W <= 106

10W <= 106

W <= 106/10 = 10.6

W <= 10.6

Therefore, the greatest possible value for the width is 10.6

Answer:

10.6

User Chrisz
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