They would not earn money when the function is equal or less to 0
then we equal 0
![(x-3)(450-3x)\leq0\text{ }](https://img.qammunity.org/2023/formulas/mathematics/high-school/40aohmjwyvyn8nqsoa7hzxbl65ifjdipxy.png)
we will have two answers when clear x
![\begin{gathered} (x_1-3)\leq0 \\ x_1\leq3 \\ (450-3x_2)\text{ }\leq\text{0} \\ 450\leq3x_2 \\ x_2\ge(450)/(3) \\ x_2\ge150 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/584r0xyg3szjtjjjk3fg7dmu3uzjcujpaj.png)
they won't make money when the ticket price is equal or less than 3 or when the ticket price is equal or greater than 150
the correct expression for not making money is :
![(-\infty,3\rbrack\text{ }\lbrack150,\infty)](https://img.qammunity.org/2023/formulas/mathematics/high-school/sn0aqvjensr18prazo8uuz9xe5w9k3a3ey.png)