Let O be an angle in quadrant II such that csc =4"Find the exact values of tan 0 and cos 0.

asked Jun 5, 2023 128k views

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$\begin{gathered} \csc (\theta)=(hypotenuse)/(opposite)=(9)/(4) \\ \end{gathered}$

The tangent function is given by:

$\tan (\theta)=(opposite)/(adjacent)=-\frac{4}{\sqrt[]{65}}$

And the cosine function is:

$\cos (\theta)=(adjacent)/(hypotenuse)=-\frac{\sqrt[]{65}}{9}$

Roman Sterlin answered Jun 11, 2023

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