Question

ootball on the ground is kicked with a speed of 20.3 m/s at an angle of 31.5° above horizontal. How high will it go before falling back down?

Answer 1

Answer: 5.74m

Step-by-step explanation:

Maximum height of projectile,

h = (u² sin²α)/2g

= ((20.3)² × (sin(31.5°))²)/(2 × 9.8)

= 5.74 m