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IBD bisects ZABC.Find mZABD, mZCBD, and mZABC.(8x +35) DVE/(11x + 23)BहैmZABD =mZCBD =m_ABC =

IBD bisects ZABC.Find mZABD, mZCBD, and mZABC.(8x +35) DVE/(11x + 23)BहैmZABD =mZCBD-example-1

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Answer

Angle ABD = 67°

Angle CBD = 67°

Angle ABC = 134°

Step-by-step explanation

BD bisecting Angle ABC means that BD divides that angle into two equal parts.

Hence, we can conclude that

Angle CBD = Angle ABD

Angle CBD = (11x + 23)°

Angle ABD = (8x + 35)°

Angle CBD = Angle ABD

11x + 23° = 8x + 35°

11x - 8x = 35° - 23°

3x = 12°

Divide both sides by 3

(3x/3) = (12°/3)

x = 4°

We can then solve for the unknowns now

Angle ABD = (8x + 35)°

= 8(4°) + 35°

= 32° + 35°

= 67°

Angle CBD = (11x + 23)°

= 11(4°) + 23°

= 44° + 23°

= 67°

Angle ABC = Angle ABD + Angle CBD

= 67° + 67°

= 134°

Hope this Helps!!!

User Ilia Shakitko
by
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