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The following balls are placed in an urn: 3 red, 3 yellow, 5 blue, and 2 green. One ball is randomly drawn from the urn. What is the probability that the ball is either yellow or green?

1 Answer

5 votes

The total number of balls available in the urn

= 3 + 3 + 5 + 2

=13

P(y or g) = 3/13 + 2/13

= 5/13

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