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Determine the molecular formula for the following compounds from the experimental data:92.3% carbon, 7.7% hydrogen, and a molecular mass of 26 amu

User Ladookie
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Answer

The molecular formula for the compound is C₂H₂

Step-by-step explanation

Given:

% composition: 92.3% carbon, 7.7% hydrogen.

Molecular mass = 26 amu

What to find:

The molecular formula for the compound.

Step-by-step solution:

Assume we have 100 grams total of the substance.

Grams C: 92.3/100 x 100 = 92.3 g

Grams H: 7.7/100 x 100 = 7.7 g

The next step is to convert the number of grams of each element into moles as shown below using the molar masses of H = 1.00784 g/mol and C = 12.011 g/mol.

Note: Mole = Mass/Molar mass.

Moles C = 92.3g/12.011 g/mol = 7.68 mol

Mole H = 7.7g/1.00784 g/mol = 7.64 mol

Now, let's divide the number of moles of each element by the smallest number obtained:

C = 7.68/7.64 = 1

H = 7.64/7.64 = 1

The empirical formula for this compound is CH

Using the molecular mass of 26 amu, the molecular formula is calculated as follows:

(Empirical mass)n = (Molecular mass)

(CH)n = 26

(12.011 + 1.00784)n = 26

(13.01884)n = 26

Divide both sides by 13.01884

n = 26/13.01884

n = 2

Moleculare formula = (CH)₂ = C₂H₂

Therefore, the molecular formula for the compound is C₂H₂

User Haitham Sweilem
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