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Use intercepts to graph the line described by the equation.-6y =-3x +18

Use intercepts to graph the line described by the equation.-6y =-3x +18-example-1
User Kodekan
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The given equation is

-6y =-3x +18

In this question, we have to use the intercepts to graph the line. For that, it is important to understand the intercepts.

X-intercept: It is the point where the graph crosses the x-axis. Therefore, the value of y is zero at that point. By following this definition, we can get the value of x-intercept.

-6y =-3x +18

-6(0) = -3x + 18. (as y=0 at x-intercept)

0 = -3x + 18

3x = 18

x = 18/3

x = 6

Hence, the point at x-intercept would be (6, 0)

y-intercept: It is the point where the graph crosses the y-axis. Therefore, the value of x is zero at that point. By following this definition, we can get the value of y-intercept.

-6y =-3x +18

-6y = -3(0) + 18. (as x=0 at y-intercept)

-6y = 0 + 18

-y = 18/6

-y = 3

y = -3

Hence, the point at y-intercept would be (0, -3)

Using these two points, you can draw the line.

You can see the line in the above graph (1 box = 5 units)

Use intercepts to graph the line described by the equation.-6y =-3x +18-example-1
Use intercepts to graph the line described by the equation.-6y =-3x +18-example-2
User Soner
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