Question

How do you put this in standard form with the y=mx+b method?

Answer 1

5x- 3y= 0

Explanation:

y=mx+b---- (3,5) 5/3=m

x y

Y= 5; M= 5/3; X=3; B=B put it together

5 = 5/3(3) + b

solve for b

5 = 5+b

b = 0

now

y= (5/3)x

step 2

Put in standard form

Ax+By=C

y=(5/3)x

Multiply by 3 both sides

3y=5x

5x- 3y= 0 -------> standard form

Answer 2

we have

point (3,5)

m=5/3

step 1

Put in slope intercept form

y=mx+b

substitute the given values

5=(5/3)(3)+b

solve for b

5=5+b

b=0

therefore

y=(5/3)x

step 2

Put in standard form

Ax+By=C

where

A is a postive integer

B and C are integers

so

y=(5/3)x

Multiply by 3 both sides

3y=5x

5x-3y=0 -------> standard form