Question

Find the zero of h(x) = 3/4x - 72

Answer 1

`h(x)=(3)/(4)x-72`

To find the zero of a function, you equal that function to 0

`(3)/(4)x-72=0`

Then, you solve the variable x:

1. Add 72 in both sides of the equation

`\begin{gathered} (3)/(4)x-72+72=0+72 \\ \\ (3)/(4)x=72 \end{gathered}`

2. Multiply both sides of the equation by 4

`\begin{gathered} 4((3)/(4)x)=72\cdot4 \\ \\ 3x=288 \end{gathered}`

3. Divide both sides of the equation into 3

`\begin{gathered} (3)/(3)x=(288)/(3) \\ \\ x=96 \end{gathered}`Then, the zero of the given function is in x=96. Coordinates (96,0)