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An object is taken to Mars. It’s mass is 15kg, it’s weight on Mars is 55.5N

What is the gravitational field strength on Mars?

User Yakobom
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1 Answer

6 votes

Answer:

Approximately
3.7\; {\rm N \cdot kg^(-1)} (or equivalently,
3.7\; {\rm m\cdot s^(-2)}.)

Step-by-step explanation:

Gravitational field strength measures the force (weight) that the field exerts on object of unit mass (e.g.,
1\; {\rm kg}.)

Divide the weight of the object by its mass to find the gravitational field strength at the position.

In this question,
\text{weight} = 55.5\; {\rm N} while
\text{mass} = 15\; {\rm kg}. Therefore, the gravitational field strength will be:


\begin{aligned} & (\text{gravitational field strength}) \\ =\; & \frac{(\text{weight})}{(\text{mass})} \\ =\; & \frac{55.5\; {\rm N}}{15\; {\rm kg}} \\ =\; & 3.7\; {\rm N \cdot kg^(-1)} \end{aligned}.

User DeadPassive
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