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The larger of two numbers is 8 less than 3 times the smaller number. The sum of the two numbers is 24. Find the SMALLER number.

User Avladov
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Step-by-step explanation

Let 'L' be the larger number and 's' be the smaller number.

We can write a system of equations for this problem:


\begin{cases}L=3s-8 \\ s+L=24\end{cases}

We can use the substitution method to find s. Replace the first equation into the second equation:


\begin{gathered} s+L=24 \\ s+(3s-8)=24 \\ (s+3s)-8=24 \\ 4s-8=24 \end{gathered}

And solve for s:


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User Mousam Singh
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