Question

A 435 mL solution was made by mixing 201 mL of cyclohexane, Which has a density of 0.78 g/mL, and 257 mL of toluene, Which has a density of 0.87 g/mL. Calculate the volume percentage of the cyclohexane in the solution. Be sure and answer has right number of significant digits.

Answer 1

`46.2\text{ \%}`

Step-by-step explanation:

Here, we want to calculate the volume percentage of cyclohexane in the solution

Mathematically, we have this as:

`\frac{volume\text{ of cyclohexane}}{\text{volume of solution}}*\text{ 100\%}`

Thus, we have the volume percentage as follows:

`(201)/(435)*\text{ 100 \% = 46.2 \% }`